-8r^2-7r-6=-10r-6r^2-10

Solution for -8r^2-7r-6=-10r-6r^2-10 equation:

-8r^2-7r-6=-10r-6r^2-10

We move all terms to the left:

-8r^2-7r-6-(-10r-6r^2-10)=0

We get rid of parentheses

-8r^2+6r^2+10r-7r+10-6=0

We add all the numbers together, and all the variables

-2r^2+3r+4=0

a = -2; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-2)·4
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*-2}=\frac{-3-\sqrt{41}}{-4}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*-2}=\frac{-3+\sqrt{41}}{-4}
$